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Reinforced concrete buildings; a treatise on the history, patents, design and erection of the principal parts entering into a modern reinforced concrete building
by:Ernest Leslie Ransome
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1912 Excerpt: ...the plate, here referred to as the " cap." p the radius of the column in inches. d the depth of the slab in inches. D the depth of the cap in...
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1912 Excerpt: ...the plate, here referred to as the " cap." p the radius of the column in inches. d the depth of the slab in inches. D the depth of the cap in inches. We will now proceed as follows: We consider the floor slab as supported on the edge of the circular plate with radius R; this plate will then have a uniform load on its surface and a concentrated load along its circumference. Finally the "cap" with radius r0 will be designed for a load concentrated on its circumference, disregarding the uniform load on its surface. The total area of the floor panel between the four column centers is L2 square inches; the total weight corresponding to this area is pL2 lbs. The area of the circular plate with radius R is irR?, the total weight on same pwR2. Hence the weight of the portion outside the circular plate becomes p L2--wR?) lbs. In the following computations, I? is always large compared with Tr2 So that this quantity may be neglected, which is also on the safe side. The load is therefore pL2, and as the circumference of the circular plate is 2irR, the load per lineal inch of circumvL2 ference becomes--5' producing a bending moment equal to vL2--= (R--r0). If measured per lineal inch of the circumference Zttr of the cap with radius r0 it becomes, by multiplication with R/r0 (Figure 125), for the circular plate. For the slab portion we have, by Formula 16: i.LJz.kJi: (33) Ci V q ci V q The value of r0 must now be such that the two depths become alike, which gives Q (34) 2 + q at the same time, the value of R is determined by the selected value of q by formula see Article 67, Formula 25. The depth of the cap. is found by the formula above, as the load again is pL2, substituting only r0 for R and p for r0, hence 9 (r.-P). (35) According to Article 84 th...
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